You are given an array (which will have a length of at least 3, but could be very large) containing integers. The array is either entirely comprised of odd integers or entirely comprised of even integers except for a single integer N. Write a method that takes the array as an argument and returns this "outlier" N.
###Examples
[2, 4, 0, 100, 4, 11, 2602, 36]
Should return: 11 (the only odd number)
[160, 3, 1719, 19, 11, 13, -21]
Should return: 160 (the only even number)
###My Answer
function findOutlier(integers){
let odd = integers.filter(i => i % 2 !== 0);
let even = integers.filter(i => i % 2 === 0);
return odd.length > even.length ? even[0] : odd[0];
}
###Best Practice
function findOutlier(int){
var even = int.filter(a=>a%2==0);
var odd = int.filter(a=>a%2!==0);
return even.length==1? even[0] : odd[0];
}